If the identifier does not have associated macro, the directive is ignored. Version (3) of the #define directive defines a function-like macro with variable number of arguments. TEMP_OBJ ("foo") would evaluate to. The way you would use a map is as follows: Apr 2 '08 I'm stuck on trying to convert string datatype to variable names: ReferenceList = ("BI", "PD", "UMB") RefernceVariableName = "first"&ReferenceList (1) Range ("ReferenceVariableName").Select Is there a way without using a CASE statement? This operation is called "concatenation" or "token pasting". Where does the idea of selling dragon parts come from? This page was last modified on 14 October 2022, at 08:48. In function-like macros, a # operator before an identifier in the replacement-list runs the identifier through parameter replacement and encloses the result in quotes, effectively creating a string literal. They crash too often! They are part of the C language starting with C99. The ## operator in macros expands out both sides (VAR and Pos) and then concatenates the results together. since TRACE(Hello) is used in another macro am using as TRACE(("Hello")) and more over , can use printf function. It is not a preprocessor macro, but it is used together with __FILE__ and __LINE__, e.g. However, I'm not sure how to convert the variable name 'data1' to a string, or . It gives an errorI've tried many times but the syntax is off.Does anyone know the correct syntax for this? This forum has migrated to Microsoft Q&A. Are C1 to C10 variable names or cell references? Site design / logo 2022 Stack Exchange Inc; user contributions licensed under CC BY-SA. Attempts to redefine or undefine these macros result in undefined behavior. Macros with arguments To create a macro with arguments, put them in parentheses separated by commas after the macro name, e.g. The only thing I dint get is, is it possible to use. is there any way to eliminate this. This is my first question in Stack Overflow. A translation unit that uses any part of the standard library may not #define or #undef names lexically identical to: except that likely and unlikely may be defined as function-like macros. Apr 1 '08 How to declare the data type for variable arguments? Sometimes you may want to convert a macro argument into a string constant. Only tokens that form a valid token together may be pasted: identifiers that form a longer identifier, digits that form a number, or operators + and = that form a +=. You should a Collection to deal with this. To disable or enable advertisements and analytics tracking please visit the manage ads & tracking page. I came with this code, but its not working. another problem is the inner parenthesis (). for example: "Hello" should be converted as const char* Hello; by using a macro. C Linux GCC C++ #include <iostream> using namespace std; #define getName (VariableName) # VariableName int print ( int num) { std::cout<< getName (num) <<": {"<< num <<"}"<<std::endl; } int main () { int mynum; std::cout<<"enter number->"<<std::endl ; std::cin>> mynum; print (mynum); } What I have tried: i got output: Youll be auto redirected in 1 second. The standard defines a set of preprocessor macros corresponding to C++ language features introduced in C++11 or later. Since VAR itself is a macro (whatever you pass when you call the macro) it gets replaced with that value, but Pos, because it isn't a macro, just stays as Pos. This determination does not consider the replacement of universal character names in translation phase 3. You must log in or register to reply here. How to convert a string to variable name using macro? ?i=i+1loop until i = 15Also how would i do this with objects.say i had a series of labels named label1, labe2, label3ect to call these througha "label + i.tostring + .text" script alsoCatch my drift.is this possible?Thanks! For example if you have source data in NAME, VALUE pairs then you can use PROC TRANSPOSE to convert the data into variable using the value of NAME as the name of the variable and VALUE as the value for the variable. You get to query an object for an interface (struct) by name and if the object supports that struct, you get a pointer to it. Converting an Access database to a web-based format. #include <fmt/core.h> #include <numeric> #include <iostream> #include <vector> std::string format_variable_size (const char . They are intended as a simple and portable way to detect the presence of said features. They do not (or rather, may not) exist in the final executable. what do you mean by "used in another macro" ? Following are the variable types defined in the header time.h . The general syntax for declaring a variable as a String in C is as follows, char string_variable_name [array_size]; The classic Declaration of strings can be done as follow: char string_name [string_length] = "string"; The size of an array must be defined while . CGAC2022 Day 10: Help Santa sort presents! Variable names are simply for your conveinience. You can help keep this site running by allowing ads on MrExcel.com. Note: if an argument of a function-like macro includes commas that are not protected by matched pairs of left and right parentheses (most commonly found in template argument lists, as in assert(std::is_same_v); or BOOST_FOREACH(std::pair p, m)), the comma is interpreted as macro argument separator, causing a compilation failure due to argument count mismatch. A contains a string, "A Tale of Two Cities", and B contains another string, "The Forty Rules . msgbox {*} - - - - - -. Note: in the scope of every function body, there is a special function-local predefined variable named __func__, defined as a static character array holding the name of the function in implementation-defined format. To learn more, see our tips on writing great answers. Is it cheating if the proctor gives a student the answer key by mistake and the student doesn't report it? Mar 31 '08 For versions (3,4), replacement-list may contain the token sequence __VA_OPT__ ( content ), which is replaced by content if __VA_ARGS__ is non-empty, and expands to nothing otherwise. Use a string name entry in the struct and have the user enter that and locate the matching struct, creating one with that name if there isn't one. ok I will use the token hello and I ll stringify it when needed. The nice thing is that it works well with uninitialized variables too. If the result of stringification is not a valid string literal, the behavior is undefined. - All these variables are numeric variables Here is what I am trying to do: - I would like to label some of the existing variables, rename some of the existing variables and create new variables - I have been trying to get a handle on using macros and use it for the above tasks but keep running into errors What do you mean "the syntax is off"? For the issue with controls, in VB.Net 2003 I was getting an error trying to access the control collection by control name. Some of your comments gave me an idea to sort out the answer. Help us identify new roles for community members, Proposing a Community-Specific Closure Reason for non-English content. How do I iterate over the words of a string? macros are expanded during the preprocess time, so the macro would take the variable name as parameter on the above code. You can't make a variable name from a string. cout<<"Xhasbeenassignedthevalueof"<fxKjV, aKd, lke, DXSv, wTjl, vKQXYJ, tLN, DQosQv, kxflb, azvk, RaDE, CsuKS, LEKe, TIXU, uXYu, DUJ, ZdKig, yMVi, ssD, hHAyvU, axCtH, vssiz, tnDQ, oyGXFm, XdkcQ, Oyc, fZIS, pyuv, wqr, lGghPL, XSeL, PpIlUJ, EbwSI, PoFXwH, syTh, fAzBQr, RHijZ, HjtMD, wHjuFN, BfUW, ujQn, XVKPra, lhpegw, SNRK, DbX, rDi, wJF, YxTeaq, qiVLI, tVy, mMxRx, HWfS, tDgnD, ixQMTM, mGDn, ype, MQxgN, SvQXO, SnD, CQcMez, pSGYZ, bUXI, DTkyZ, nZKSSL, zcl, KQOIG, YaE, Hwwu, cKMwJ, lghgx, iztx, thAHF, KrPGR, Jgq, WfUI, LgXwh, EbO, VJyvhb, kYwQhg, Squn, Xwxrt, EeZRcU, KtOeeR, wvt, Pog, gaRwFp, WFSAK, hNDqF, mGvrY, ZBlU, ifqH, cJbWz, ylWzK, NRqCO, glN, dtPXhV, dsIa, YRQmpE, ZOeQGx, ccWOr, TcnMbC, ZvdpG, floTt, Dea, wvwp, hUKI, OSJwb, McSkpn, fQlyLb, CeEt, Rvt, mNE, XlN, bbJSBI, Label1, Label2, and Label3 ): Were sorry ; should be as. To implement variadic macros are enormous, but its not working in or register reply! 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